Iodine is sparingly soluble in pure water. However, it does `dissolve’ in solutions containing excess iodide ion because of the following reaction:
I–(aq) + I2(aq) I3–(aq) K = 710 |
[I3^-] to [I2].
5.00×10-2 mol of I2 is added to 1.00 L of 5.00×10-1 M KI solution.
The solution above is diluted to 12.00 L.
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